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Question
A swimming pool is 40 m long and 15 m wide. Its shallow and deep ends are 1.5 m and 3 m deep respectively. If the bottom of the pool slopes uniformly, find the amount of water in liters required to fill the pool.
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Solution
Area of cross-section of the solid = `1/2( 1.5 + 3 ) xx ( 40 )`m2
= `1/2`( 4.5 ) × ( 40 ) m2
= 90 m2
Volume of solid = Area of cross section × Length
= 90 × 15 m3
= 1350 m3
= 1350000 liters ....( Since 1m3 = 1000L )
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