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A Swimming Pool is 40 M Long and 15 M Wide. Its Shallow and Deep Ends Are 1.5 M and 3 M Deep Respectively. If the Bottom of the Pool Slopes Uniformly,

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Question

A swimming pool is 40 m long and 15 m wide. Its shallow and deep ends are 1.5 m and 3 m deep respectively. If the bottom of the pool slopes uniformly, find the amount of water in liters required to fill the pool.

Sum
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Solution

Area of cross-section of the solid = `1/2( 1.5 + 3 ) xx ( 40 )`m2

= `1/2`( 4.5 ) × ( 40 ) m2

= 90 m2

Volume of solid = Area of cross section × Length

= 90 × 15 m3

= 1350 m3

= 1350000 liters     ....( Since 1m3 = 1000L )

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Cross Section of Solid Shapes
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Chapter 20: Solids [Surface Area and Volume of 3-D Solids] - Exercise 21 (B) [Page 273]

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Selina Concise Mathematics [English] Class 9 ICSE
Chapter 20 Solids [Surface Area and Volume of 3-D Solids]
Exercise 21 (B) | Q 2 | Page 273
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