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Question
A rectangular field is 112 m long and 62 m broad. A cubical tank of edge 6 m is dug at each of the four corners of the field and the earth so removed is evenly spread on the remaining field. Find the rise in level.
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Solution
Vol. of the tank= vol. of earth spread
4 x 63 m3 = ( 112 x 62 - 4 x 62 ) m2 x Rise in level
Rise in level = `( 4 xx 6^3)/ ( 112 xx 62 - 4 xx 6^2)`
= `( 864) / ( 6800)`
= 0.127 m
= 12.7 cm
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