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The following function has a removable discontinuity? If it has a removable discontinuity, redefine the function so that it become continuous : f(x) =3x+2, for -4≤x≤-2=2x-3; for -2<x≤6

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Question

The following function has a removable discontinuity? If it has a removable discontinuity, redefine the function so that it become continuous :

f(x) `{:(= 3x + 2",",  "for"  -4 ≤ x ≤-2),(= 2x - 3";",  "for"  -2 < x ≤ 6):}`

Sum
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Solution

f(x) `{:(= 3x + 2",",  "for"  -4 ≤ x ≤-2),(= 2x - 3";",  "for"  -2 < x ≤ 6):}`

`lim_(x -> -2^-) "f"(x) = lim_(x -> -2^-) (3x + 2)`

= 3(– 2) + 2

= – 4

`lim_(x -> -2^+) "f"(x) = lim_(x -> -2^+) (2x - 3)`

= 2(– 2) – 3

= – 7

∴ `lim_(x -> -2^-) "f"(x) ≠ lim_(x -> -2^+) "f"(x)`

∴ `lim_(x -> -2^-) "f"(x)` does not exist

∴ f(x) is discontinuous at x = – 2

This discontinuity is irremovable.

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Chapter 8: Continuity - EXERCISE 8.1 [Page 174]

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