Advertisements
Advertisements
Question
The figure formed by joining the mid-points of the adjacent sides of a quadrilateral is a
Options
parallelogram
rectangle
square
rhombus
Advertisements
Solution
Figure can be drawn as:

Let ABCD be a quadrilateral such that P,Q,R and S are the mid-points of side AB,BC,CD and DA respectively.
In ΔABC,P and Q are the mid-points of AB and BC respectively.
Therefore,
PQ || AC and `PQ = 1/2 AC`
Similarly, we have
RS || ACand `RS = 1/2 AC`
Thus,
PQ || RS and PQ = RS
Therefore, PQRSis a parallelogram.
The figure formed by joining the mid-points of the adjacent sides of a quadrilateral is a
parallelogram.
Hence the correct choice is (a).
APPEARS IN
RELATED QUESTIONS
In ΔABC and ΔDEF, AB = DE, AB || DE, BC = EF and BC || EF. Vertices A, B and C are joined to vertices D, E and F respectively (see the given figure). Show that
(i) Quadrilateral ABED is a parallelogram
(ii) Quadrilateral BEFC is a parallelogram
(iii) AD || CF and AD = CF
(iv) Quadrilateral ACFD is a parallelogram
(v) AC = DF
(vi) ΔABC ≅ ΔDEF.

In a parallelogram ABCD, ∠D = 135°, determine the measures of ∠A and ∠B
The following statement are true and false.
In a parallelogram, the diagonals bisect each other.
The following statement are true and false .
If all the angles of a quadrilateral are equal, it is a parallelogram .
The following statement are true and false .
If all the sides of a quadrilateral are equal it is a parallelogram.
If ABCD is a rhombus with ∠ABC = 56°, find the measure of ∠ACD.
Complete the following statement by means of one of those given in brackets against each:
Consecutive angles of a parallelogram are ...................
PQRS is a quadrilateral, PR and QS intersect each other at O. In which of the following case, PQRS is a parallelogram?
PQ = 7 cm, QR = 7 cm, RS = 8 cm, SP = 8 cm
If one angle of a parallelogram is 24° less than twice the smallest angle, then the measure of the largest angle of the parallelogram is
ABCD is a parallelogram and E and F are the centroids of triangles ABD and BCDrespectively, then EF =
