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The feasible solution for a LPP is shown in Figure. Let Z = 3x – 4y be the objective function. Minimum of Z occurs at ______.

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Question

The feasible solution for a LPP is shown in Figure. Let Z = 3x – 4y be the objective function. Minimum of Z occurs at ______.

Options

  • (0, 0)

  • (0, 8)

  • (5, 0)

  • (4, 10)

MCQ
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Solution

The feasible solution for a LPP is shown in Figure. Let Z = 3x – 4y be the objective function. Minimum of Z occurs at (0, 8).

Explanation:

Corner points Value of Z = 3x – 4y  
O(0, 0) Z = 0  
A(5, 0) Z = 3(5) – 0 = 15  
B(6, 5) Z = 3(6) – 4(5) = – 2  
C(6, 8 Z = 3(6) – 4(8) = – 14  
D(4, 10) Z = 3(4) – 4(10) = – 28 ← Minimum
E(0, 8) Z = 3(0) – 4(8) = – 32  
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Chapter 12: Linear Programming - Exercise [Page 255]

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NCERT Exemplar Mathematics Exemplar [English] Class 12
Chapter 12 Linear Programming
Exercise | Q 27 | Page 255

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