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Karnataka Board PUCPUC Science Class 11

The Electric Field at a Point Associated with a Light Wave is

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Question

The electric field at a point associated with a light wave is `E = (100  "Vm"^-1) sin [(3.0 xx 10^15 "s"^-1)t] sin [(6.0 xx 10^15 "s"^-1)t]`.If this light falls on a metal surface with a work function of 2.0 eV, what will be the maximum kinetic energy of the photoelectrons?

(Use h = 6.63 × 10-34J-s = 4.14 × 10-15 eV-s, c = 3 × 108 m/s and me = 9.1 × 10-31kg)

Sum
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Solution

Given :-

`E = 100 sin [(3 xx 10^-15 "s"^-1)t] sin [(6 xx 10^-15 "s"^-1)t]`

= `100 xx 1/2 cos [(9 xx 10^15 "s"^-1)t] - cos[(3 xx 10^15 "s"^-1)t]`

The values of angular frequency `ω` are `9 xx 10^15` and `3 xx 10^15`.

Work function of the metal surface, `phi = 2  "eV"`

Maximum frequency,

`v = ω_(max)/(2pi) = (9 xx 10^15)/(2pi) Hz`

From Einstein's photoelectric equation, kinetic energy, 

K = hv - `phi`

`⇒ K = 6.63 xx 10^-34 xx (9 xx 10^15)/(2pi) xx 1/(1.6 xx 10^-19) - 2 "eV"`

⇒ K = 3.938 eV

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Chapter 42: Photoelectric Effect and Wave-Particle Duality - Exercises [Page 366]

APPEARS IN

HC Verma Concepts of Physics Volume 1 and 2 [English]
Chapter 42 Photoelectric Effect and Wave-Particle Duality
Exercises | Q 22 | Page 366

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