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Maharashtra State BoardSSC (English Medium) 10th Standard

The distance between point P(2, 2) and Q(5, x) is 5 cm, then the value of x = ______. A) 2 B) 6 C) 3 D) 1

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Question

The distance between point P(2, 2) and Q(5, x) is 5 cm, then the value of x = ______.

Options

  • 2

  • 6

  • 3

  • 1

MCQ
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Solution

The distance between point P(2, 2) and Q(5, x) is 5 cm, then the value of x = 6.

Explanation:

Let P(x1, y1) = P(2, 2) and Q(x2, y2) = Q(5, x)

Here, x1 = 2, y1 = 2, x2 = 5, y2 = x

By distance formula,

d(P, Q) = `sqrt((x_2 - x_1)^2 + (y_2 - y_1)^2)`

∴ `5 = sqrt((5 - 2)^2 + (x - 2)^2)`

∴ `5 = sqrt(9 + x^2 - 4x + 4)`

∴ 52 = x2 – 4x + 13   ...[Squaring both sides]

∴ 25 = x2 – 4x + 13 

∴ x2 – 4x + 13 – 25 = 0

∴ x2 – 4x – 12 = 0

∴ (x – 6) (x + 2) = 0

∴ x – 6 = 0 or x + 2 = 0

∴ x = 6 or x = –2

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Chapter 5: Co-ordinate Geometry - Exercise

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