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Question
The currents flowing in the two coils of self-inductance L1 = 16 mH and L2 = 12 mH are increasing at the same rate. If the power supplied to the two coil is equal, find the ratio of the currents ?
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Solution
Power, \[P = IV\]
\[\frac{I_1}{I_2} = \frac{V_2}{V_1} \left( \text { as P } \text { is same } \right)\]
\[ \Rightarrow \frac{I_1}{I_2} = \frac{3}{4}\]
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