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Question
The currents flowing in the two coils of self-inductance L1 = 16 mH and L2 = 12 mH are increasing at the same rate. If the power supplied to the two coil is equal, find the ratio of induced voltages ?
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Solution
Induced voltage, \[V = L\frac{d I}{d t}\]
\[\frac{V_1}{V_2} = \frac{L_1}{L_2} \left( as \frac{d I}{d t} \text { is same } \right)\]
\[ \Rightarrow \frac{V_1}{V_2} = \frac{16}{12} = \frac{4}{3}\]
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