Advertisements
Advertisements
प्रश्न
The currents flowing in the two coils of self-inductance L1 = 16 mH and L2 = 12 mH are increasing at the same rate. If the power supplied to the two coil is equal, find the ratio of induced voltages ?
Advertisements
उत्तर
Induced voltage, \[V = L\frac{d I}{d t}\]
\[\frac{V_1}{V_2} = \frac{L_1}{L_2} \left( as \frac{d I}{d t} \text { is same } \right)\]
\[ \Rightarrow \frac{V_1}{V_2} = \frac{16}{12} = \frac{4}{3}\]
APPEARS IN
संबंधित प्रश्न
Explain the phenomenon of self induction
Define the coefficient of self-induction.
A magnetic flux of 8 × 10−4 weber is linked with each turn of a 200-turn coil when there is an electric current of 4 A in it. Calculate the self-inductance of the coil.
Obtain an expression for the self-inductance of a solenoid.
Two coils of wire A and B are placed mutually perpendicular as shown. When current is changed in any one coil.

The frequency of γ-rays, X-rays and ultraviolet rays are a, b and c respectively. Then, ______.
The coefficient of self inductance of a solenoid is 0.18 mH. If a core of soft iron of relative permeability 900 is inserted, then the coefficient of self inductance will become nearly ______.
An inductor may store energy in
An average induced emf of 0.20 V appears in a coil when the current in it is changed from 5A in one direction to 5A in the opposite direction in 0.20 sec. Find the self induction of the coil.
