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Question
Consider a small cube of volume 1 mm3 at the centre of a circular loop of radius 10 cm carrying a current of 4 A. Find the magnetic energy stored inside the cube.
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Solution
Given:-
Current in the loop, i = 4 A
Radius of the loop, r = 10 cm = 0.1 m
Volume of the cube, V = 1 mm3 = 1 × 10-9m
Magnetic field intensity at the centre of the circular loop:-
\[B = \frac{\mu_0 i}{2r}\]
\[ = \frac{(4\pi \times {10}^{- 7} ) \times 4}{2 \times 0 . 1}\]
\[ = 8\pi \times {10}^{- 6} T\]
Magnetic energy density = \[\frac{B^2}{2 \mu_0}\]
otal energy stored in volume V:-
\[U=\frac{B^2 V}{2 \mu_0}\]
\[= \frac{(8\pi \times {10}^{- 6} )^2 \times (1 \times {10}^{- 9} )}{(4\pi \times {10}^{- 7} ) \times 2}\]
\[ = 8\pi \times {10}^{- 14} J\]
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