Question

An average induced emf of 0.20 V appears in a coil when the current in it is changed from 5A in one direction to 5A in the opposite direction in 0.20 sec. Find the self induction of the coil.

Options

• 4 × 10^-3 H

• 2 × 10^-3 H

• `2sqrt2 xx 10^-3` H

• `3sqrt3 xx 10^-1` H

Answer 1

4 × 10^-3 H

Explanation:

As we know,

e = `"L" "dI"/"dt"`

`=> 0.20 = ("L"(5 - (-5)))/0.20`

`=> (0.20 xx 0.20)/(5 + 5) = L`

⇒ 4 × 10^-3 H