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The cross section of a swimming pool is a trapezium whose shallow and deep ends are 1 m and 3 m respectively. If the length of the pool is 50 m and its width is 1.5 m, calculate the volume of water

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Question

The cross section of a swimming pool is a trapezium whose shallow and deep ends are 1 m and 3 m respectively. If the length of the pool is 50 m and its width is 1.5 m, calculate the volume of water it holds.

Sum
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Solution

Area of cross-section
= Area of trapezium

= `(1)/(2) xx ("sum of parallel sides") xx "height"`

= `(1)/(2) xx (1 + 3) xx 1.5`
= 3m2
Volume of the pool
= Area of cross-section x length
= 3 x 50
= 150m3
∴ The volume of the pool is 150m3.

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Cross Section of Solid Shapes
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Chapter 20: Surface Areas and Volume of Solids - Exercise 25.3

APPEARS IN

Frank Mathematics Part 1 [English] Class 9 ICSE
Chapter 20 Surface Areas and Volume of Solids
Exercise 25.3 | Q 11

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