Question

The cross section of a swimming pool is a trapezium whose shallow and deep ends are 1 m and 3 m respectively. If the length of the pool is 50 m and its width is 1.5 m, calculate the volume of water it holds.

Answer 1

Area of cross-section
= Area of trapezium

= `(1)/(2) xx ("sum of parallel sides") xx "height"`

= `(1)/(2) xx (1 + 3) xx 1.5`
= 3m²
Volume of the pool
= Area of cross-section x length
= 3 x 50
= 150m³
∴ The volume of the pool is 150m³.