हिंदी

The Cross-section of a Tunnel Perpendicular to Its Length is a Trapezium Abcd as Shown in the Following Figure; Also Given That: Am = Bn; Ab = 7 M; Cd = 5 M the Height of the Tunnel is 2.4 M - Mathematics

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प्रश्न

The cross-section of a tunnel perpendicular to its length is a trapezium ABCD as shown in the following figure; also given that:

AM = BN; AB = 7 m; CD = 5 m. The height of the tunnel is 2.4 m. The tunnel is 40 m long. Calculate:

(i) The cost of painting the internal surface of the tunnel (excluding the floor) at the rate of Rs. 5 per m2 (sq. meter).

(ii) The cost of paving the floor at the rate of Rs. 18 per m2.

योग
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उत्तर

The cross-section of a tunnel is of the trapezium-shaped ABCD in which  AB = 7 m, CD = 5 m and AM = BN. The height is 2.4 m and its length is 40 m.

(i) AM = BN =`( 7 - 5 )/( 2 )= ( 2 )/( 2 ) =1"m"`

∴ In ΔADM,

AD2 = AM2 + DM2      ...[ Using Pythagoras theorem ]

= 12 + (2 . 4)2

= 1 + 5.76

= `sqrt6.76`

= 2.6

AD = 2.6 m 

Perimeter of the cross-section of the tunnel = ( 7 + 2.6 + 2.6 + 5 ) m = 17.2 m

Length = 40 m

∴ The internal surface area of the tunnel ( except the floor ) 

= ( 17.2 × 40 - 40 × 7) m2

= ( 688 - 280 ) m2

= 408 m

Rate of painting = Rs. 5 per m2

Hence, total cost of painting = Rs. 5 × 408 = Rs. 2040

(ii) Area of floor of tunnel = l × b = 40 × 7 = 280 m2

Rate of cost of paving = Rs. 18 per m

Total cost = 280 × 18 = Rs. 5040

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Cross Section of Solid Shapes
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 21: Solids [Surface Area and Volume of 3-D Solids] - Exercise 21 (B) [पृष्ठ २७३]

APPEARS IN

सेलिना Concise Mathematics [English] Class 9 ICSE
अध्याय 21 Solids [Surface Area and Volume of 3-D Solids]
Exercise 21 (B) | Q 3 | पृष्ठ २७३

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