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Question
The best reagent for converting, 2-phenylpropanamide into 1- phenylethanamine is ______.
Options
\[\ce{excess H2/Pt}\]
\[\ce{NaOH/Br2}\]
\[\ce{NaBH4 /methanol}\]
\[\ce{LiAlH4 /ether}\]
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Solution
The best reagent for converting, 2-phenylpropanamide into 1- phenylethanamine is \[\ce{NaOH/Br2}\].
Explanation:
\[\begin{array}{cc}
\ce{CH3 - CH - CONH2 ->[Br/NaOH][(Hofmann's bromamide reaction)] CH3 - CH - NH2}\\
\phantom{}|\phantom{..............................................}|\phantom{..}\\
\phantom{....}\ce{\underset{2-Phenylpropanamide}{C6H5}\phantom{................................}\underset{1-Phenyletanamine}{C6H5}\phantom{...}}
\end{array}\]
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