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Question
The base of an isosceles triangle is 6 cm and its area is 12 sq. cm. Find its perimeter.
Sum
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Solution
Given: Base = 6 cm, Area = 12 cm2 (isosceles triangle)
Step-wise calculation:
1. Area formula:
Area = `1/2` × base × height
2. Solve for height:
height = `(2 xx "Area")/"base"`
= `(2 xx 12)/6`
= 4 cm
3. Half the base
= `6/2`
= 3 cm
In the right triangle formed, equal side
= `sqrt("half‑base"^2 + "height"^2)`
= `sqrt(3^2 + 4^2)`
= `sqrt(9 + 16)`
= `sqrt(25)`
= 5 cm
4. Perimeter = base + 2 × (equal side)
= 6 + 2 × 5
= 16 cm
The perimeter of the triangle is 16 cm.
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