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Question
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Solution
Depth of water= 6 cm = 0 .06 m.
Density of water = 1000 kgm-3.
Acceleration due to gravity = 10 ms-2.
We know pressure
P = h x p x g.
P = 0.06 x 1000 x 10 = 600 Nm-2= 600 Pa.
Area of base of cylindrical vessel = 300 cm2 = 300 x 10-4m2= 0.03 m2.
We know
Thrust = pressure x area.
Thrust =600 x 0.03 = 18 N.
So thrust acting on the base of the vessel is 18 N.
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