Question

The base of a cylindrical vessel measures 300 cm². Water (density = 1000 kg m^-3) is poured into it up to a depth of 6 cm. Calculate the pressure and thrust of water on the base. (g = 10 m s^-2)

Answer 1

Depth of water= 6 cm = 0 .06 m.

Density of water = 1000 kgm^-3.
Acceleration due to gravity = 10 ms^-2.

We know pressure
P = h x p x g.
P = 0.06 x 1000 x 10 = 600 Nm^-2= 600 Pa.

Area of base of cylindrical vessel = 300 cm² = 300 x 10^-4m²= 0.03 m².

We know
Thrust = pressure x area.
Thrust =600 x 0.03 = 18 N.
So thrust acting on the base of the vessel is 18 N.