Advertisements
Advertisements
Question
The arms of a beam balance are 20 cm and 21 cm, but the pans are of equal weight. By the method of double weighing the weights are found to be 1000 g and 20 g. Find the actual weight of the body
Advertisements
Solution
m = mass of each pan
m0 = actual mass of the body
(100 + m)20 = (m + m0) 21
Dividing the two equations
`21/20 = ((100 + "m")20)/((20 + "m") 21)`
1.1 (20 + m) = (1000 + m)
22 + 1.1m = 1000 + m
0.1m = 978
m = 9780g
APPEARS IN
RELATED QUESTIONS
State the condition when a body is in static equilibrium.
State the condition when a body is in dynamic equilibrium.
State two conditions for a body acted upon by several forces to be in equilibrium.
A meter scale is pivoted at its mid point and a 50 g mass suspended from the 20 cm mark. What mass balances the ruler when suspended from 65 cm mark?
Give scientific reason for the following:
While climbing a hill you will try to bend your body forward.
A faulty balance of equal arms but pans of unequal weight is used to find the weight of a body. By the method of double weighing the weights are found as 8 kg and 8.2 kg. Find the actual weight of the body.
In equilibrium algebraic sum of moments of all forces about the point of rotation is ______.
Define the term momentum.
Mention any two conditions for the stability of a body?
