Advertisements
Advertisements
प्रश्न
The arms of a beam balance are 20 cm and 21 cm, but the pans are of equal weight. By the method of double weighing the weights are found to be 1000 g and 20 g. Find the actual weight of the body
Advertisements
उत्तर

m = mass of each pan
m0 = actual mass of the body
(100 + m)20 = (m + m0) 21

Dividing the two equations
`21/20 = ((100 + "m")20)/((20 + "m") 21)`
1.1 (20 + m) = (1000 + m)
22 + 1.1m = 1000 + m
0.1m = 978
m = 9780g
APPEARS IN
संबंधित प्रश्न
What do you mean by an equilibrium of a body?
The figure shows a uniform metre rule placed on a fulcrum at its mid-point O and having a weight 40 gf at the 10 cm mark and a weight of 20 gf at the 90 cm mark.
- Is the metre rule in equilibrium? If not how will the rule turn?
- How can the rule be brought in equilibrium by using an additional weight of 40 gf?

What do you mean by the state of equilibrium? What are the conditions for stable equilibrium?
Give scientific reason for the following:
While climbing a hill you will try to bend your body forward.
The moon revolving around the earth is in ______ equilibrium.
Explain why It is easier to knock down a boy who is standing on one foot than one who is standing on two.
What is meant by equilibrium and state the conditions of equilibrium of a body?
Give an experiment to verify the principle of moments.
Give one example of dynamic equilibrium.
