Advertisements
Advertisements
प्रश्न
A faulty balance of equal arms but pans of unequal weight is used to find the weight of a body. By the method of double weighing the weights are found as 8 kg and 8.2 kg. Find the actual weight of the body.
Advertisements
उत्तर
m0= actual weight
mL = weight of leftpan
mR = weight of right pan
mL + 8 = m0 + mR
mR + 8.2 kg = m0 + m2
adding the two equations
mL + mR + 16.2kg = 2m0 + m2 +mR
⇒ 16.2 = 2m0
m0 = 8.1 kg
APPEARS IN
संबंधित प्रश्न
What do you mean by the state of equilibrium? What are the conditions for stable equilibrium?
The arms of a beam balance are 20 cm and 21 cm, but the pans are of equal weight. By the method of double weighing the weights are found to be 1000 g and 20 g. Find the actual weight of the body
In equilibrium algebraic sum of moments of all forces about the point of rotation is ______.
Define the term momentum.
Explain why It is easier to knock down a boy who is standing on one foot than one who is standing on two.
Explain when we carry weight, on one hand, we bend on the other side.
What is a couple?
A ball is placed on a compressed spring. When the spring is released, the ball is observed to fly away.
(i) What form of energy does the compressed spring possess?
(ii) Why does the ball fly away?
When a stone tied to a string is rotated in a horizontal plane, the tension in the string provides ______ force necessary for circular motion.
Give one example of dynamic equilibrium.
