Advertisements
Advertisements
Question
A faulty balance of equal arms but pans of unequal weight is used to find the weight of a body. By the method of double weighing the weights are found as 8 kg and 8.2 kg. Find the actual weight of the body.
Advertisements
Solution
m0= actual weight
mL = weight of leftpan
mR = weight of right pan
mL + 8 = m0 + mR
mR + 8.2 kg = m0 + m2
adding the two equations
mL + mR + 16.2kg = 2m0 + m2 +mR
⇒ 16.2 = 2m0
m0 = 8.1 kg
APPEARS IN
RELATED QUESTIONS
In a beam balance, when the beam is balanced in a horizontal position, it is in ______ equilibrium.
State two condition for a body acted upon by several forces to be in equilibrium.
State the principle of moments. Give one device as an application of it
The figure shows a uniform metre rule placed on a fulcrum at its mid-point O and having a weight 40 gf at the 10 cm mark and a weight of 20 gf at the 90 cm mark.
- Is the metre rule in equilibrium? If not how will the rule turn?
- How can the rule be brought in equilibrium by using an additional weight of 40 gf?
State the principle of moments. A meter scale is pivoted at 30 cm mark and it is in equilibrium when a mass of 40 g is suspended from 10 cm mark. Calculate the mass of the ruler.
Give scientific reason for the following:
In a moving bus the standing passenger stands keeping both his legs apart.
What makes a balance faulty?
A ball is placed on a compressed spring. When the spring is released, the ball is observed to fly away.
(i) What form of energy does the compressed spring possess?
(ii) Why does the ball fly away?
Give one example of static equilibrium.
