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Question
A faulty balance of equal arms but pans of unequal weight is used to find the weight of a body. By the method of double weighing the weights are found as 8 kg and 8.2 kg. Find the actual weight of the body.
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Solution
m0= actual weight
mL = weight of leftpan
mR = weight of right pan
mL + 8 = m0 + mR
mR + 8.2 kg = m0 + m2
adding the two equations
mL + mR + 16.2kg = 2m0 + m2 +mR
⇒ 16.2 = 2m0
m0 = 8.1 kg
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