Advertisements
Advertisements
प्रश्न
The arms of a beam balance are 20 cm and 21 cm, but the pans are of equal weight. By the method of double weighing the weights are found to be 1000 g and 20 g. Find the actual weight of the body
Advertisements
उत्तर
m = mass of each pan
m0 = actual mass of the body
(100 + m)20 = (m + m0) 21
Dividing the two equations
`21/20 = ((100 + "m")20)/((20 + "m") 21)`
1.1 (20 + m) = (1000 + m)
22 + 1.1m = 1000 + m
0.1m = 978
m = 9780g
APPEARS IN
संबंधित प्रश्न
In a beam balance, when the beam is balanced in a horizontal position, it is in ______ equilibrium.
State the condition when a body is in static equilibrium.
State the principle of moments. A meter scale is pivoted at 30 cm mark and it is in equilibrium when a mass of 40 g is suspended from 10 cm mark. Calculate the mass of the ruler.
Give scientific reason for the following:
While climbing a hill you will try to bend your body forward.
Give scientific reason for the following:
In a moving bus the standing passenger stands keeping both his legs apart.
In figure, a uniform bar of length l m is supported at its ends and loaded by a weight W kgf at its middle. In equilibrium, find the reactions R1 and R2 at the ends.
`["Hint:" "In equilibrium" "R"_1 + "R"_2 = "W" "and" "R"_1 xx l/2 = "R"_2 xx l/2]`
Explain why It is easier to knock down a boy who is standing on one foot than one who is standing on two.
State two conditions when the work done by a force acting on a body is zero.
Explain the concept which is used in the continuous movement of the Thanjavur doll?
A non uniform beam of weight 120 N pivoted at one end is shown in the diagram below. Calculate the value of F to keep the beam in equilibrium.
