Advertisements
Advertisements
प्रश्न
A non uniform beam of weight 120 N pivoted at one end is shown in the diagram below. Calculate the value of F to keep the beam in equilibrium.
Advertisements
उत्तर
Given:
Weight of the beam, W = 120 N
The center of gravity (C.G.) is at a distance from the pivot = 0.20 m
F = 0.80 m
Formula:
W × distance to C.G. = F × distance to F
Solution:
∴ Anticlockwise moment = Clockwise moment
W × distance to C.G. = F × distance to F
120 × 0.20 = F × 0.80
24 = 0.80 F
`F = 24/0.80`
= 30 N
The value of F required to keep the beam in equilibrium is 30 N.
APPEARS IN
संबंधित प्रश्न
Define equilibrium.
State the principle of moments. A meter scale is pivoted at 30 cm mark and it is in equilibrium when a mass of 40 g is suspended from 10 cm mark. Calculate the mass of the ruler.
A meter scale is pivoted at its mid point and a 50 g mass suspended from the 20 cm mark. What mass balances the ruler when suspended from 65 cm mark?
State the principle of moments.
Explain when we carry weight, on one hand, we bend on the other side.
What do you mean by dynamic and static equilibrium? Give one example of each.
One end of a spring is kept fixed while the other end is stretched by a force as shown in the diagram.
(i) Copy the diagram and mark on it the direction of the restoring force.
(ii) Name one instrument which works on the above principle.
Give an experiment to verify the principle of moments.
What are the three types of stability of an object?
