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Question
The area of cross-sections of the pump plunger and press plunger of a hydraulic press is 0.02 m2 and 8 m2 respectively. If the hydraulic press overcomes a load of 800 kgf, calculate the force acting on the pump plunger.
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Solution
Load on the press plunger = L = 800 kgf
Let the effort acting on the pump plunger = E
Area of cross-section of pump plunger = A1 = 0.02 m2
Area of cross-section of press plunger = A2 = 8 m2
Now, `"L"/"E"="A"_2/"A"_1`
`800/"E"=8/0.02=800/2=400`
E = `800/400` = 2kgf
⇒ Force acting on the pump plunger = 2kgf
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