Advertisements
Advertisements
प्रश्न
The area of cross-sections of the pump plunger and press plunger of a hydraulic press is 0.02 m2 and 8 m2 respectively. If the hydraulic press overcomes a load of 800 kgf, calculate the force acting on the pump plunger.
Advertisements
उत्तर
Load on the press plunger = L = 800 kgf
Let the effort acting on the pump plunger = E
Area of cross-section of pump plunger = A1 = 0.02 m2
Area of cross-section of press plunger = A2 = 8 m2
Now, `"L"/"E"="A"_2/"A"_1`
`800/"E"=8/0.02=800/2=400`
E = `800/400` = 2kgf
⇒ Force acting on the pump plunger = 2kgf
APPEARS IN
संबंधित प्रश्न
Define one pascal (Pa), the S.I. unit of pressure.
Explain the principle of a hydraulic machine. Name two devices which work on this principle.
In a hydraulic machine, a force of 2 N is applied on the piston of area of cross section 10 cm2. What force is obtained on its piston of area of cross section 100 cm2 ?
The areas of pistons in a hydraulic machine are 5 cm2 and 625 cm2. What force on the smaller piston will support a load of 1250 N on the larger piston? State any assumption which you make in your calculation.
Select the correct option.
Pressure at a point inside a liquid does not depend on
How does the liquid pressure on a diver change according to the following condition:
When the driver moves horizontally
What is the use of altimeter?
State Pascal's law.
Do all liquids exert pressure?
State Pascal’s law.
