Question

In a hydraulic machine, a force of 2 N is applied on the piston of area of cross section 10 cm². What force is obtained on its piston of area of cross section 100 cm² ?

Answer 1

Force on narrow piston , F₁ = 2N
Area of cross - section of narrow piston , A₁ = 10 cm²
Let Force on wider piston be F₂
Area of cross - section of wider piston , A₂ = 100 cm²
By the principle of hydraulic machine , 
Pressure on narrow piston = pressure on wider piston
or, `"F"_1/"A"_1 = "F"_2/"A"_2`

or , `2/10 = "F"_2/100`

or , `"F"_2 = 20  "N"`