Advertisements
Advertisements
प्रश्न
The areas of pistons in a hydraulic machine are 5 cm2 and 625 cm2. What force on the smaller piston will support a load of 1250 N on the larger piston? State any assumption which you make in your calculation.
Advertisements
उत्तर
Area of small piston A1 = 5 cm2
Area of wider piston, A2 = 625 cm2
Force on small piston be F1
Force on wider piston or load, F2 = 1250 N
By the principle of hydraulic machine,
Pressure on narrow piston = pressure on wider piston
or, `F_1/A_1 = F_2/A_2`
or, `F_1/5 = 1250/625`
or, `F_1 = 1250/625 xx 5`
or `F_1 = 10` N
Assumption: No friction or leakage of liquid happens.
संबंधित प्रश्न
In a hydraulic machine, a force of 2 N is applied on the piston of area of cross section 10 cm2. What force is obtained on its piston of area of cross section 100 cm2 ?
If the mechanical advantage of the handle of the pump plunger is 8, calculate the force applied at the end of the handle of the pump plunger.
The atmospheric pressure at a place is 650 mm of Hg. Calculate this pressure in Pascals (Pa).
The following figure shows a manometer containing a liquid of density p. The limb P of the manometer is connected to a vessel V and the limb Q is open to atmosphere. The difference in the levels of liquid in the two limbs of the manometer is h as shown in the diagram. The atmospheric pressure is P0.
(i) What is the pressure on the liquid surface in the limb Q?
(ii) What is the pressure on the liquid surface in the limb P?
State Pascal's law.
State two uses of a hydraulic press.
For what purpose is the acid battery hydrometer used?
What are Force multipliers?
An iceberg of density 700 kg/m3 is floating in the water of density 1000 kg/m3. The percentage of the volume of ice cube outside the water is:
