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Question
In a hydraulic machine, a force of 2 N is applied on the piston of area of cross section 10 cm2. What force is obtained on its piston of area of cross section 100 cm2 ?
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Solution
Force on narrow piston , F1 = 2N
Area of cross - section of narrow piston , A1 = 10 cm2
Let Force on wider piston be F2
Area of cross - section of wider piston , A2 = 100 cm2
By the principle of hydraulic machine ,
Pressure on narrow piston = pressure on wider piston
or, `"F"_1/"A"_1 = "F"_2/"A"_2`
or , `2/10 = "F"_2/100`
or , `"F"_2 = 20 "N"`
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