Advertisements
Advertisements
Question
The area of base of a cylindrical vessel is 300 cm2. Water (density= 1000 kg m-3) is poured into it up to a depth of 6 cm. Calculate : (a) the pressure and (b) the thrust of water on the base. (g = 10m s-2.
Advertisements
Solution
Given Area of base of vessel , a = 300 cm2 = 300 × 10-4 m2
Density of water , ρ = 1000 kg m-3
Depth , h = 6 cm = 0.06 m
Acceleration due to gravity , g = 10 ms-2
(a) Pressure = hρg = 0.06 × 1000 × 10 = 600 pascal
(b) Thrust , T = pressure × area = 600 × 300 × 10-4 = 18 N
RELATED QUESTIONS
What causes buoyant force (or upthrust) on a boat ?
Fill in the blank with suitable word :
It is the................. force which makes objects appear lighter in water.
Define the term Density of a substance.
What physical quantity is measured in bar?
State the laws of liquid pressure.
What do you understand by the term upthrust of a fluid? Describe an experiment to show its existence.
It is easier to lift a heavy stone under water than in air. Explain.
A block of wood is floating on water with its dimensions 50 cm x 50 cm x 50 cm inside water. Calculate the buoyant force acting on the block. Take g = 9.8 N kg-1.
What is the centre of buoyancy? State its position for a floating body with respect to the centre of gravity of the body.
In a fluid, buoyant force exists because the pressure at the ______ of an object is greater than the pressure at the top.
