Advertisements
Advertisements
Question
A hammer exerts a force of 1.5 N on each of the two nails A and B. The area of cross section of tip of nail A is 2 mm2 while that of nail B is 6 mm2. Calculate pressure on each nail in pascal.
Advertisements
Solution
Force exerted , F = 1.5 N
Area of cross - section of tip of nail A , a1 = 2 mm2 = `2 xx 10^-6` m2
Area of cross - section of tip of nail B , a1 = 6 mm2 = `6 xx 10^-6 "m"^2`
Pressure on nail A = `"F"/"a"_1 = 1.5/(2 xx 10^-6) = 7.5 xx 10^5` pascal
Pressure on nail B = `"F"/"a"_2 = 1.5/(6 xx 10^-6) = 2.5 xx 10^5` pascal
APPEARS IN
RELATED QUESTIONS
A boy get into a floating boat.
What happens to the buoyant force on the boat ?
Define the term relative density of a substance.
Define the term thrust. State its S.I. unit.
What is meant by pressure? State its S.I. unit.
Complete the following sentence :
Pressure of a liquid at a given depth is .................. To the density of the liquid.
The pressure P1 at a certain depth in river water and P2 at the same depth in sea water are related as :
Prove that the loss in weight of a body when immersed wholly or partially in a liquid is equal to the buoyant force (or upthrust) and this loss is because of the difference in pressure exerted by liquid on the upper and lower surfaces of the submerged part of body.
Complete the following sentence.
Mass = .................... × density
What is the centre of buoyancy? State its position for a floating body with respect to the centre of gravity of the body.
If the buoyant force is less, the object will float.
