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The 7th term of the given Arithmetic Progression (A.P.) 1/a, (1/a + 1), (1/a + 2)... is ______. - Mathematics

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Question

The 7th term of the given Arithmetic Progression (A.P.) `1/a, (1/a + 1), (1/a + 2)`... is ______.

Options

  • `(1/a + 6)`

  • `(1/a + 7)`

  • `(1/a + 8)`

  • `(1/a + 7^7)`

MCQ
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Solution

The 7th term of the given Arithmetic Progression (A.P.)

`1/a, (1/a + 1), (1/a + 2)`... is `bbunderline((1/a + 6))`

Explanation:

Given A.P. is `1/a, (1/a + 1), (1/a + 2)`

Here, first term, A = `1/a`

Common difference D = `1/a + 1 - 1/a` = 1

Then, 7th term of A.P. = A + (n – 1)D

= `1/a + (7 - 1) xx 1`

= `1/a + 6`

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Chapter 9: Arithmetic and geometric progression - Exercise 9F [Page 200]

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Nootan Mathematics [English] Class 10 ICSE
Chapter 9 Arithmetic and geometric progression
Exercise 9F | Q 11. | Page 200
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