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Question
The $$n$$th term from the end of an A.P. whose first term, last term and common difference are $$a$$, $$l$$ and $$d$$ respectively, is given by:
Options
$$l + (n + 1)d$$
$$l - (n - 1)d$$
$$l + (n - 1)d$$
$$l - (n + 1)d$$
MCQ
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Solution
l – (n – 1)d
Explanation:
Counting backward from the last term, the nth term from the end is $$l - (n - 1)d$$.
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