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Suppose, in Certain Conditions Only Those Transitions Are Allowed to Hydrogen Atoms in Which the Principal Quantum Number N Changes by 2. (A) Find the Smallest Wavelength - Physics

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Question

Suppose, in certain conditions only those transitions are allowed to hydrogen atoms in which the principal quantum number n changes by 2. (a) Find the smallest wavelength emitted by hydrogen. (b) List the wavelength emitted by hydrogen in the visible range (380 nm to 780 nm).

Sum
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Solution

Given:

Possible transitions:

From n1 = 1 to n2 = 3

         n1 = 2 to n2 = 4

(a) Here, n1 = 1 and n2 = 3

Energy, `E = 13.6 (1/n_1^2- 1/n_2^2)`

`E = 13.6 (1/1 - 1/9)`

`= 13.6xx8/9 ....... (i)`

Energy (E) is also given by

`E = (hc)/lamda`

Here, h = Planck constant

  c = Speed of the light

λ  = Wavelength of the radiation

`therefore E = (6.63xx10^-34xx3xx10^2)/lamda`   ........(i)

`"Equanting equation (1) and (2) , we have"`

`lamda = (6.63xx10^-34xx3xx10^8xx9)/(13.6xx8)`

= 0.027 ×  10-7  = 103 nm

(b) Visible radiation comes in Balmer series.
As 'n' changes by 2, we consider n = 2 to n = 4.

`"Energy" , E_1 = 13.6 (1/n_1^2 - 1/n_2^2)`

= `13.6 xx (1/4 - 1/16)`

=2.55 eV

If `lamda_1` is the wavelength of the radiation, when transition takes place between quantum number n = 2 to n = 4, then

`255 = 1242/lamda_1`

or  λ= 487 nm

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The Line Spectra of the Hydrogen Atom
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Chapter 21: Bohr’s Model and Physics of Atom - Exercises [Page 384]

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HC Verma Concepts of Physics Vol. 2 [English] Class 11 and 12
Chapter 21 Bohr’s Model and Physics of Atom
Exercises | Q 20 | Page 384

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