Advertisements
Advertisements
Question
State the two Kirchhoff’s rules used in the analysis of electric circuits and explain them.
Advertisements
Solution
- Junction rule: At any junction, the sum of the currents entering the junction is equal to the sum of currents leaving the junction.
- Loop rule: The algebraic sum of changes in potential around any closed loop involving resistors and cells in the loop is zero.
APPEARS IN
RELATED QUESTIONS
Given the resistances of 1 Ω, 2 Ω, 3 Ω, how will be combine them to get an equivalent resistance of (11/5) Ω?
In the circuit shown in the figure below, E1 and E2 are two cells having emfs 2 V and 3 V respectively, and negligible internal resistance. Applying Kirchhoff’s laws of electrical networks, find the values of currents l1 and I2.
Twelve wires each having a resistance of 3 Ω are connected to form a cubical network. A battery of 10 V and negligible internal resistance is connected across the diagonally opposite corners of this network. Determine its equivalent resistance and the current along each edge of the cube.
State Kirchhoff ’s voltage rule.
State the principle of potentiometer.
A copper wire of 10-6 m2 area of cross-section, carries a current of 2 A. If the number of electrons per cubic meter is 8 × 1028, calculate the current density and average drift velocity.
The instrument for the accurate measurement of the e.m.f of a cell is ______.
Three resistors having resistances r1, r2 and r3 are connected as shown in the given circuit. The ratio `i_3/i_1` of currents in terms of resistances used in the circuit is:
Why are alloys used for making standard resistance coils?
The circuit in figure shows two cells connected in opposition to each other. Cell E1 is of emf 6V and internal resistance 2Ω; the cell E2 is of emf 4V and internal resistance 8Ω. Find the potential difference between the points A and B.
