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Question
Solve the following problem :
Given that `sum "p"_1"q"_1 = 300, sum "p"_0"q"_1 = 320, sum "p"_0"q"_0` = 120, and Marshall- Edgeworth’s Price Index Number is 120, find `sum"p"_1"q"_0` and Paasche’s Price Index Number.
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Solution
Given, P01(M-E) = `120, sum "p"_1"q"_1 = 300, sum "p"_0"q"_1 = 320, sum "p"_0"q"_0 = 120`
P01(M–E) = `(sum"p"_1"q"_0 + sum"p"_1"q"_1)/(sum"p"_0"q"_0 + sum"p"_0"q"_1) xx 100`
∴ 120 = `(sum"p"_1"q"_0 + 300)/(120 + 320) xx 100`
∴ 120 = `(sum"p"_1"q"_0 + 300)/(440) xx 100`
∴ `sum"p"_1"q"_0 + 300 = (120 xx 440)/(100)`
∴ `sum"p"_1"q"_0 + 300` = 528
∴ `sum"p"_1"q"_0` = 528 – 300
∴ `sum"p"_1"q"_0` = 228
Paasche’s Price Index Number:
P01(P) = `(sum"p"_1"q"_1)/(sum"p"_0"q"_1) xx 100`
= `(300)/(320) xx 100`
= 93.75
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