Advertisements
Advertisements
Question
Solve the following equation for A, if tan 3 A = 1
Advertisements
Solution
tan 3 A = 1
tan 3 A = tan 45°
3 A = tan 45°
A = 15°
APPEARS IN
RELATED QUESTIONS
Find the magnitude of angle A, if 2 sin A cos A - cos A - 2 sin A + 1 = 0
If 4 cos2 x = 3 and x is an acute angle;
find the value of :
(i) x
(ii) cos2 x + cot2 x
(iii) cos 3x (iv) sin 2x
Solve the following equation for A, if 2 sin A = 1
Calculate the value of A, if (tan A - 1) (cosec 3A - 1) = 0
Find the magnitude of angle A, if tan A - 2 cos A tan A + 2 cos A - 1 = 0
If A = B = 60°, verify that: sin(A - B) = sinA cosB - cosA sinB
In a rectangle ABCD, AB = 20cm, ∠BAC = 60°, calculate side BC and diagonals AC and BD.
Find lengths of diagonals AC and BD. Given AB = 24 cm and ∠BAD = 60°.
Evaluate the following: cosec 54° - sec 36°
Evaluate the following: `(5cot5° cot15° cot25° cot35° cot45°)/(7tan45° tan55° tan65° tan75° tan85°) + (2"cosec"12° "cosec"24° cos78° cos66°)/(7sin14° sin23° sec76° sec67°)`
