Advertisements
Advertisements
Question
If sec2θ = cosec3θ, find the value of θ if it is known that both 2θ and 3θ are acute angles.
Advertisements
Solution
sec2θ = cosec3θ
⇒ sec2θ = sec(90° - 3θ)
⇒ 2θ = 90° - 3θ
⇒ 5θ = 90°
⇒ θ = 18°.
APPEARS IN
RELATED QUESTIONS
Solve for x : 2 cos 3x - 1 = 0
Find the value of 'A', if cosec 3A = `(2)/sqrt(3)`
Find lengths of diagonals AC and BD. Given AB = 24 cm and ∠BAD = 60°.
Find:
a. BC
b. AD
c. AC
Find x and y, in each of the following figure:
In right-angled triangle ABC; ∠B = 90°. Find the magnitude of angle A, if:
a. AB is `sqrt(3)` times of BC.
B. BC is `sqrt(3)` times of BC.
A ladder is placed against a vertical tower. If the ladder makes an angle of 30° with the ground and reaches upto a height of 18 m of the tower; find length of the ladder.
Evaluate the following: `(sec32° cot26°)/(tan64° "cosec"58°)`
Express each of the following in terms of trigonometric ratios of angles between 0° and 45°: cosec64° + sec70°
Evaluate the following: `(2sin25° sin35° sec55° sec65°)/(5tan 29° tan45° tan61°) + (3cos20° cos50° cot70° cot40°)/(5tan20° tan50° sin70° sin40°)`
