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Question
Evaluate the following: `(2sin28°)/(cos62°) + (3cot49°)/(tan41°)`
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Solution
`(2sin28°)/(cos62°) + (3cot49°)/(tan41°)`
= `(2sin(90° - 62°))/(cos62°) + (3cot(90° - 41°))/(tan41°)`
= `(2cos62°)/(cos62°) + (3tan41°)/(tan41°)`
= 2 + 3
= 5.
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