Advertisements
Advertisements
Question
Evaluate the following: `(5sec68°)/("cosec"22°) + (3sin52° sec38°)/(cot51° cot39°)`
Advertisements
Solution
`(5sec68°)/("cosec"22°) + (3sin52° sec38°)/(cot51° cot39°)`
= `(5sec(90° - 22°))/("cosec"22°) + (3sin52° sec(90° - 52°))/(cot51° cot(90° - 51°)`
= `(5cos22°)/("cosec"22°) + (3sin52° "cosec"52°)/(cot51° tan51°)`
= `5 + (3sin52° xx 1/(sin52°))/(cot51° xx 1/(cot51°)`
= `5 + (3)/(1)`
= 5 + 3
= 8.
APPEARS IN
RELATED QUESTIONS
If 2 cos (A + B) = 2 sin (A - B) = 1;
find the values of A and B.
Find the value of 'A', if 2cos 3A = 1
Solve for 'θ': `sin θ/(3)` = 1
In the given figure, PQ = 6 cm, RQ = x cm and RP = 10 cm, find
a. cosθ
b. sin2θ- cos2θ
c. Use tanθ to find the value of RQ
In a rectangle ABCD, AB = 20cm, ∠BAC = 60°, calculate side BC and diagonals AC and BD.
Find lengths of diagonals AC and BD. Given AB = 24 cm and ∠BAD = 60°.
Find x and y, in each of the following figure:
In the given figure, a rocket is fired vertically upwards from its launching pad P. It first rises 20 km vertically upwards and then 20 km at 60° to the vertical. PQ represents the first stage of the journey and QR the second. S is a point vertically below R on the horizontal level as P, find:
a. the height of the rocket when it is at point R.
b. the horizontal distance of point S from P.
Evaluate the following: cot27° - tan63°
Express each of the following in terms of trigonometric ratios of angles between 0° and 45°: cos84° + cosec69° - cot68°
