Advertisements
Advertisements
Question
Find lengths of diagonals AC and BD. Given AB = 24 cm and ∠BAD = 60°.
Advertisements
Solution

The given figure is a rhombus as all sides are equal. we know that diagonals of a rhombus bisect each other at right angles and also bisect the angle of vertex.
Let the diagonals AC and BD intersect each other at O.
⇒ OA = `"OC" - (1)/(2)"AC", "OB" = "OD" = (1)/(2)"BD"`, ∠AOB = 90°
Now, ∠BAD = 60°
⇒ ∠OAB = `(1)/(2)∠"BAD"` = 30°
In right-angled AOB,
sin30° = `"OB"/"AB"`
⇒ `(1)/(2) = "OB"/(24)`
⇒ OB = 12cm
cos30° = `"OA"/"AB"`
⇒ `sqrt(3)/(2) = "OA"/(24)`
⇒ OA = `12sqrt(3)"cm"`
∴ Length of diagonal AC
= 2 x OA
= `2 xx 2sqrt(3)`
= `24sqrt(3)"cm"`
And, length of diagonal BD
= 2 x OB
= 2 x 12
= 24cm.
APPEARS IN
RELATED QUESTIONS
If 4 cos2 x° - 1 = 0 and 0 ∠ x° ∠ 90°,
find:(i) x°
(ii) sin2 x° + cos2 x°
(iii) `(1)/(cos^2xx°) – (tan^2 xx°)`
If `sqrt(3)` sec 2θ = 2 and θ< 90°, find the value of
cos2 (30° + θ) + sin2 (45° - θ)
Find the value 'x', if:
In the given figure; ∠B = 90°, ∠ADB = 30°, ∠ACB = 45° and AB = 24 m. Find the length of CD.
Evaluate the following: `(tan42°)/(cot48°) + (cos33°)/(sin57°)`
Evaluate the following: `(2sin28°)/(cos62°) + (3cot49°)/(tan41°)`
Evaluate the following: `(5cot5° cot15° cot25° cot35° cot45°)/(7tan45° tan55° tan65° tan75° tan85°) + (2"cosec"12° "cosec"24° cos78° cos66°)/(7sin14° sin23° sec76° sec67°)`
If A, B and C are interior angles of ΔABC, prove that sin`(("A" + "B")/2) = cos "C"/(2)`
Prove the following: sin58° sec32° + cos58° cosec32° = 2
Prove the following: sin230° + cos230° = `(1)/(2)sec60°`
