Advertisements
Advertisements
प्रश्न
Find lengths of diagonals AC and BD. Given AB = 24 cm and ∠BAD = 60°.
Advertisements
उत्तर

The given figure is a rhombus as all sides are equal. we know that diagonals of a rhombus bisect each other at right angles and also bisect the angle of vertex.
Let the diagonals AC and BD intersect each other at O.
⇒ OA = `"OC" - (1)/(2)"AC", "OB" = "OD" = (1)/(2)"BD"`, ∠AOB = 90°
Now, ∠BAD = 60°
⇒ ∠OAB = `(1)/(2)∠"BAD"` = 30°
In right-angled AOB,
sin30° = `"OB"/"AB"`
⇒ `(1)/(2) = "OB"/(24)`
⇒ OB = 12cm
cos30° = `"OA"/"AB"`
⇒ `sqrt(3)/(2) = "OA"/(24)`
⇒ OA = `12sqrt(3)"cm"`
∴ Length of diagonal AC
= 2 x OA
= `2 xx 2sqrt(3)`
= `24sqrt(3)"cm"`
And, length of diagonal BD
= 2 x OB
= 2 x 12
= 24cm.
APPEARS IN
संबंधित प्रश्न
If sin x + cos y = 1 and x = 30°, find the value of y
State for any acute angle θ whether cos θ increases or decreases as θ increases.
If sin 3A = 1 and 0 < A < 90°, find `tan^2A - (1)/(cos^2 "A")`
Solve for x : cos (2x - 30°) = 0
Solve for x : sin2 x + sin2 30° = 1
Find the value of 'A', if (2 - cosec 2A) cos 3A = 0
In a trapezium ABCD, as shown, AB ‖ DC, AD = DC = BC = 24 cm and ∠A = 30°. Find: length of AB
Find the value of 'y' if `sqrt(3)` = 1.723.
Given your answer correct to 2 decimal places.
Evaluate the following: sin35° sin45° sec55° sec45°
If A + B = 90°, prove that `(tan"A" tan"B" + tan"A" cot"B")/(sin"A" sec"B") - (sin^2"B")/(cos^2"A")` = tan2A
