Advertisements
Advertisements
प्रश्न
If sin x + cos y = 1 and x = 30°, find the value of y
Advertisements
उत्तर
Given that x = 30°
sin x + cos y = 1
sin 30° + cos y = 1
cos y = 1 – sin 30°
cos y = 1 –`(1)/(2)`
cos y = `(1)/(2)`
cos y = cos 60°
y = 60°
संबंधित प्रश्न
Solve for x : cos `(x/(2)+10°) = (sqrt3)/(2)`
Solve for x : cos2 30° + cos2 x = 1
Find the value of 'A', if (1 - cosec A)(2 - sec A) = 0
If `sqrt(3)` sec 2θ = 2 and θ< 90°, find the value of
cos2 (30° + θ) + sin2 (45° - θ)
In a right triangle ABC, right angled at C, if ∠B = 60° and AB = 15units, find the remaining angles and sides.
Find x and y, in each of the following figure:
Evaluate the following: `(sec32° cot26°)/(tan64° "cosec"58°)`
Express each of the following in terms of trigonometric ratios of angles between 0° and 45°: cos84° + cosec69° - cot68°
Evaluate the following: `(3sin^2 40°)/(4cos^2 50°) - ("cosec"^2 28°)/(4sec^2 62°) + (cos10° cos25° cos45° "cosec"80°)/(2sin15° sin25° sin45° sin65° sec75°)`
Prove the following: `(tan(90° - θ)cotθ)/("cosec"^2 θ)` = cos2θ
