Advertisements
Advertisements
प्रश्न
Evaluate the following: `(sin62°)/(cos28°)`
Advertisements
उत्तर
`(sin62°)/(cos28°)`
= `(sin(90° - 28°))/(cos28°)`
= `(cos28°)/(cos28°)`
= 1.
APPEARS IN
संबंधित प्रश्न
Use the given figure to find:
(i) tan θ°
(ii) θ°
(iii) sin2θ° - cos2θ°
(iv) Use sin θ° to find the value of x.
If 4 cos2 x = 3 and x is an acute angle;
find the value of :
(i) x
(ii) cos2 x + cot2 x
(iii) cos 3x (iv) sin 2x
Solve the following equation for A, if 2 sin A = 1
Calculate the value of A, if (tan A - 1) (cosec 3A - 1) = 0
Solve for x : 2 cos (3x − 15°) = 1
If sin α + cosβ = 1 and α= 90°, find the value of 'β'.
If A = B = 60°, verify that: cos(A - B) = cosA cosB + sinA sinB
In a trapezium ABCD, as shown, AB ‖ DC, AD = DC = BC = 24 cm and ∠A = 30°. Find: length of AB
In the given figure, if tan θ = `(5)/(13), tan α = (3)/(5)` and RS = 12m, find the value of 'h'.
In right-angled triangle ABC; ∠B = 90°. Find the magnitude of angle A, if:
a. AB is `sqrt(3)` times of BC.
B. BC is `sqrt(3)` times of BC.
