Advertisements
Advertisements
प्रश्न
Find the length of AD. Given: ∠ABC = 60°, ∠DBC = 45° and BC = 24 cm.
Advertisements
उत्तर

In ΔABC,
tan60° = `"AC"/"BC"`
⇒ `sqrt(3) = "AC"/(24)`
⇒ AC = `24sqrt(3)"cm"`
In ΔDBC,
tan45° = `"DC"/"BC"`
⇒ 1 = `"DC"/(24)`
⇒ DC = 24cm
Now,
AC = AD + DC
⇒ AD
= AC - DC
= `24sqrt(3) - 24`
= `24(sqrt(3) - 1)"cm"`.
APPEARS IN
संबंधित प्रश्न
Find the magnitude of angle A, if 2 cos2 A - 3 cos A + 1 = 0
Find the value of 'A', if `sqrt(3)cot"A"` = 1
Solve for 'θ': cot2(θ - 5)° = 3
If A = B = 60°, verify that: sin(A - B) = sinA cosB - cosA sinB
If A = B = 60°, verify that: tan(A - B) = `(tan"A" - tan"B")/(1 + tan"A" tan"B"")`
If `sqrt(3)` sec 2θ = 2 and θ< 90°, find the value of
cos2 (30° + θ) + sin2 (45° - θ)
The perimeter of a rhombus is 100 cm and obtuse angle of it is 120°. Find the lengths of its diagonals.
In the given figure; ∠B = 90°, ∠ADB = 30°, ∠ACB = 45° and AB = 24 m. Find the length of CD.
Evaluate the following: `(sin62°)/(cos28°)`
If A, B and C are interior angles of ΔABC, prove that sin`(("A" + "B")/2) = cos "C"/(2)`
