Advertisements
Advertisements
प्रश्न
Find the length of AD. Given: ∠ABC = 60°, ∠DBC = 45° and BC = 24 cm.
Advertisements
उत्तर
In ΔABC,
tan60° = `"AC"/"BC"`
⇒ `sqrt(3) = "AC"/(24)`
⇒ AC = `24sqrt(3)"cm"`
In ΔDBC,
tan45° = `"DC"/"BC"`
⇒ 1 = `"DC"/(24)`
⇒ DC = 24cm
Now,
AC = AD + DC
⇒ AD
= AC - DC
= `24sqrt(3) - 24`
= `24(sqrt(3) - 1)"cm"`.
APPEARS IN
संबंधित प्रश्न
Solve the following equation for A, if 2cos2A = 1
Solve for x : sin2 x + sin2 30° = 1
Find the value of 'A', if 2 sin 2A = 1
Solve for 'θ': `sin θ/(3)` = 1
Solve for 'θ': `sec(θ/2 + 10°) = (2)/sqrt(3)`
If tanθ= cotθ and 0°≤ θ ≤ 90°, find the value of 'θ'.
If A = B = 60°, verify that: tan(A - B) = `(tan"A" - tan"B")/(1 + tan"A" tan"B"")`
Evaluate the following: `(sec32° cot26°)/(tan64° "cosec"58°)`
Evaluate the following: sin22° cos44° - sin46° cos68°
If A + B = 90°, prove that `(tan"A" tan"B" + tan"A" cot"B")/(sin"A" sec"B") - (sin^2"B")/(cos^2"A")` = tan2A
