If tanθ= cotθ and 0°≤ θ ≤ 90°, find the value of 'θ'.

बेरीज

tanθ = cotθ
⇒ tanθ = `(1)/tanθ`
⇒ tan²θ = 1
⇒ tanθ = 1
⇒ θ = 45°.

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Trigonometric Equation Problem and Solution

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पाठ 27: Trigonometrical Ratios of Standard Angles - Exercise 27.1

पाठ 27 Trigonometrical Ratios of Standard Angles
Exercise 27.1 | Q 10

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