Advertisements
Advertisements
प्रश्न
Solve for 'θ': `sec(θ/2 + 10°) = (2)/sqrt(3)`
बेरीज
Advertisements
उत्तर
`sec(θ/2 + 10°) = (2)/sqrt(3)`
⇒ `sec(θ/2 + 10°)` = sec 30°
⇒ `θ/(2) + 10°` = 30°
⇒ `θ/(2)` = 20°
⇒ θ = 40°.
shaalaa.com
Trigonometric Equation Problem and Solution
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
APPEARS IN
संबंधित प्रश्न
Solve the following equation for A, if sec 2A = 2
Calculate the value of A, if (sec 2A - 1) (cosec 3A - 1) = 0
If 3 tan A - 5 cos B = `sqrt3` and B = 90°, find the value of A
Solve for x : 3 tan2 (2x - 20°) = 1
If tanθ= cotθ and 0°≤ θ ≤ 90°, find the value of 'θ'.
Find the value of 'x' in each of the following:
Find x and y, in each of the following figure:
Evaluate the following: `(sec32° cot26°)/(tan64° "cosec"58°)`
Evaluate the following: tan(78° + θ) + cosec(42° + θ) - cot(12° - θ) - sec(48° - θ)
If sin(θ - 15°) = cos(θ - 25°), find the value of θ if (θ-15°) and (θ - 25°) are acute angles.
