Advertisements
Advertisements
प्रश्न
Solve for 'θ': cot2(θ - 5)° = 3
Advertisements
उत्तर
cot2(θ - 5)° = 3
⇒ cot(θ - 5)° = `sqrt(3)`
⇒ cot(θ - 5)° = cot 30°
⇒ (θ - 5)° = 30°
⇒ θ = 30°+ 5°
⇒ θ = 35°.
APPEARS IN
संबंधित प्रश्न
Solve the following equations for A, if `sqrt3` tan A = 1
Solve the following equation for A, if 2 sin 3 A = 1
Solve for x : sin2 60° + cos2 (3x- 9°) = 1
If A = B = 60°, verify that: tan(A - B) = `(tan"A" - tan"B")/(1 + tan"A" tan"B"")`
Find the value of 'x' in each of the following:
Find the length of AD. Given: ∠ABC = 60°, ∠DBC = 45° and BC = 24 cm.
Find the length of EC.
Evaluate the following: tan(78° + θ) + cosec(42° + θ) - cot(12° - θ) - sec(48° - θ)
If sin(θ - 15°) = cos(θ - 25°), find the value of θ if (θ-15°) and (θ - 25°) are acute angles.
If A, B and C are interior angles of ΔABC, prove that sin`(("A" + "B")/2) = cos "C"/(2)`
